之前面试曾经有人问过我二叉树的问题,今天看了一下
# -*- coding: utf-8 -*-
"""
Created on Mon Apr 03 19:58:58 2017
@author: Administrator
"""
class node(object):
def __init__(self, data=None, left=None, right=None):
self.data = data
self.left = left
self.right = right
# 深度
def depth(tree):
if tree == None:
return 0
left, right = depth(tree.left), depth(tree.right)
return max(left, right) + 1
# 前序遍历
def pre_order(tree):
if tree == None:
return
print(tree.data)
pre_order(tree.left)
pre_order(tree.right)
# 中序遍历
def mid_order(tree):
if tree == None:
return
mid_order(tree.left)
print(tree.data)
mid_order(tree.right)
# 后序遍历
def post_order(tree):
if tree == None:
return
post_order(tree.left)
post_order(tree.right)
print(tree.data)
# 层次遍历
def level_order(tree):
if tree == None:
return
q = []
q.append(tree)
while q:
current = q.pop(0)
print(current.data)
if current.left != None:
q.append(current.left)
if current.right != None:
q.append(current.right)
# 按层次打印
def level2_order(tree):
if tree == None:
return
q = []
q.append(tree)
results = {}
level = 0
current_level_num = 1
nextlevelnum = 0
d = []
while q:
current = q.pop(0)
current_level_num -= 1
d.append(current.data)
if current.left != None:
q.append(current.left)
nextlevelnum += 1
if current.right != None:
q.append(current.right)
nextlevelnum += 1
if current_level_num == 0:
current_level_num = nextlevelnum
nextlevelnum = 0
results[level] = d
d = []
level += 1
print(results)
if __name__ == '__main__':
tree = node('D', node('B', node('A'), node('C')), node('E', right=node('G', node('F'))))
print('前序遍历:')
pre_order(tree)
print('\n')
print('中序遍历:')
mid_order(tree)
print('\n')
print('后序遍历:')
post_order(tree)
print('\n')
print("层次遍历")
level2_order(tree)